A pair of closely spaced parallel conducting plates, charged with equal and oppo

Question

A pair of closely spaced parallel conducting plates, charged with equal and opposite electric charges, produces a uniform electric field in the region between                 them. In designing a cutting-edge device that will revolutionize the electronics industry, you set up such a pair of plates with a separation of 0.815 mm between                 them and charge them so that the direction of the electric field in their interior region is from plate A to plate B. Your idea requires that electrons, when                 released from rest at one of the plates, reach the other plate at the speed of 1.65% of the speed of light. (The speed of light is c = 3.00

Explanation / Answer

Since the field points from A to B, and electrons are negatively charged. They will have to leave from plate B.

To find the field strength, we will apply the conservation of energy law.

The PE of the charge on plate B will equal the KE of the moving charges

PE = qV = qEd

KE = .5mv2

qEd = .5mv2

E = .5mv2/qd

The speed is .0165 X 3 X 108 = 4.95 x 106 m/s

E = (.5)(9.11 X 10-31)(4.95 x 106)2/(1.6 X 10-19)(8.15 X 10-4)

E = 5.73 X 104 N/C

(PLEASE CHECK CALCULTATION AGAIN)

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