Help me please! An object is launched horizontally from a known height with a kn
ID: 2277433 • Letter: H
Question
Help me please!
An object is launched horizontally from a known height with a known speed. Which two equations will allow you to find its range (the horizontal distance at which it hits the ground.)
Options are:
An object is launched from a known height at a known speed and a known angle above the horizontal. Which single equation allows you to find the vertical component of its velocity vector just before it hits the ground?
Options are:
x = xo + vox t + 1/2 ax t2 vx = vox + ax t vx2 = vox2 + 2 ax (x-xo) y = yo + voy t + 1/2 ay t2 vy = voy + ay t vy2 = voy2 + 2 ay (y-yo)Explanation / Answer
a)x = xo+ voxt + 1/2 axt2
y = yo+ voyt + 1/2 ayt2
from 2nd equation u can find t as Voy =0 and ay=9.8
put t in 1st equation. find x which is range.
b)vy= voy+ ayt
Voy is known ay is known=9.8 so Vy can be found.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.