Two copper wires, one double the diameter of the other, have the same current fl

Question

Two copper wires, one double the diameter of the other, have the same current flowing through them. If the thinner wire has a drift speed v1, and the thicker wire has a drift speed v2, how do the drift speeds of the charge carriers compare? A. v1 = v2 B. 4 v1 = v2 C. 2 v1 = v2 D. v1 = 4 v2 E. v1 = 2 v2 Two copper wires, one double the diameter of the other, have the same current flowing through them. If the thinner wire has a drift speed v1, and the thicker wire has a drift speed v2, how do the drift speeds of the charge carriers compare? A. v1 = v2 B. 4 v1 = v2 C. 2 v1 = v2 D. v1 = 4 v2 E. v1 = 2 v2

Explanation / Answer

Drift velocity V = i/neA

Velocity is inversly prop to Area

fot thinner wire A= pi d/2)^2 = pi d^2/4

giver d2 = 2d1

for thicker wire A = pi (2d1/2)^2 = 4 pi d^2/4

so V1 /V2 = A2/A1

V1./V2 = 4

V1= 4 V2

optionD

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