A 0.840- kg glider on a level air track is joined by strings to two hanging mass
ID: 2277250 • Letter: A
Question
A 0.840- kg glider on a level air track is joined by strings to two hanging masses. As seen in the figure, the mass on the left is 4.85 kg and the one on the right is 3.62 kg The strings have negligible mass and pass over light, frictionless pulleys. Find the acceleration of the masses when the air flow is turned off and the coefficient of friction between the glider and the track is 0.41. Take positive to be an acceleration to the right.
Find the tension in the string on the left between the glider and the 4.85- kg mass when the air flow is turned off and the coefficient of friction between the glider and the track is 0.41.
Find the tension in the string on the right between the glider and the 3.62- kg mass when the air flow is turned off and the coefficient of friction between the glider and the track is 0.41
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A 0.840- kg glider on a level air track is joined by strings to two hanging masses. As seen in the figure, the mass on the left is 4.85 kg and the one on the right is 3.62 kg The strings have negligible mass and pass over light, frictionless pulleys. Find the acceleration of the masses when the air flow is turned off and the coefficient of friction between the glider and the track is 0.41. Take positive to be an acceleration to the right. Find the tension in the string on the left between the glider and the 4.85- kg mass when the air flow is turned off and the coefficient of friction between the glider and the track is 0.41. Find the tension in the string on the right between the glider and the 3.62- kg mass when the air flow is turned off and the coefficient of friction between the glider and the track is 0.41Explanation / Answer
The question asks you to assume positive acceleration to the right the acceleration you worked out is correct, to work out the tension you subsitute the acceleration in to one of your equations for each side.
You should get, For the right, T = 39.12344 N (unrounded)
and For the Left, T = 42.68 N (unrounded)
the exact value for acceleration is (-2382/2375) ms-2 subsituting this in to your previous equations when working out acceleration may give you a different answer this also reduces accuracy errors.
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