The nose of an ultralight plane is pointed south, and its airspeed indicator sho
ID: 2276120 • Letter: T
Question
The nose of an ultralight plane is pointed south, and its airspeed indicator shows 42 m/s. The plane is in a 18 m/s wind blowing toward the southwest relative to earth.
Please show equations used and why. Thank you.
Explanation / Answer
vP/W = -42*j. (i denote x-axis and j denote y-axis)
vW/E= -18*sin45*i-18*cos45*j=-12.7*i-12.7*j.
we have
vP/E=vP/W+vW/E=-54.7*j-12.7*i.
so vx=-12.7 and vy=-54.7
b. magnitude v=sqrt(12.7^2+54.7^2)=56.15(m/s).
c. direction (with x-axis counter clockwise be positive).
tan alpha = -54.7 / -12.7
so alpha = 256.92(deg)
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