A particle having charge q = +1.80 A particle having charge q = +1.80 mu C and m

Question

A particle having charge q = +1.80

A particle having charge q = +1.80 mu C and mass m = 0.010 0 kg is connected to a string that is L = 1.20 m long and tied to the pivot point P in the figure below. The particle, string, and pivot point all lie on a frictionless, horizontal table. The particle is released from rest when the string makes an angle ? = 60.0 degree with a uniform electric field of magnitude E = 310 V/m. Determine the speed of the particle when the string is parallel to the electric field. Your response differs from the correct answer by more than 10%. Double check your calculations. m/s

Explanation / Answer

change in potential energy due to electric field will result in the change in kinetic energy

So, .5*m*v^2= q*E*delX ( where m is the mass of particle=.01kg, v its velocity, q is the charge on particle=1.8

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