Now she is out on a hike and comes to the left bank of a river. There is no brid

Question

Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 m away horizontally and 2.5 m, vertically below. If she long jumps from the edge of the left bank at 45 ? with the speed calculated in A, how long, or short, of the opposite bank will she land? (Figure 1) Express your answer using two significant figures. v0 = 9.4   m/s   Now she is out on a hike and comes to the left bank of a river. There is no bridge and the right bank is 10.0 m away horizontally and 2.5 m, vertically below. If she long jumps from the edge of the left bank at 45 ? with the speed calculated in A, how long, or short, of the opposite bank will she land? (Figure 1) Express your answer using two significant figures. v0 = 9.4   m/s   9.4 v0 = 9.4   m/s  

Explanation / Answer

initial vertical velocity = 9.4sin(45) upwards

v^2 - [9.4sin(45)]^2 = 2^9.8*2.5

v = 9.653

v = u + at

9.653 = -9.4sin(45) + 9.8*T

T = 1.663

horizontal distance = 9.4cos(45)*T = 11.05 m

she lands 1.05m long from the bank . [away from the bank]

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.