Two loudspeakers, 5.0 m apart and facing each other, play identical sounds of th

Question

Two loudspeakers, 5.0 m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them, where there is a maximum of sound intensity. Moving from this point toward one of the speakers, you encounter a minimum of sound intensity when you have moved 0.30 m. A) What is the frequency of the sound (in Hz)? B) If the frequency is then increased while you remain 0.30 from the center, what is the first frequency for which that location will be a maximum of sound intensity (in Hz)?

Explanation / Answer

4m apart, in phase at centre. For minimum you need 1/2 wavelength difference, so if you moved .25 metres one way, the wavelength must be .5m.
Using 343m/sec as sound velocity, 343/.5 = 686Hz.

For a max sound there, you need 1 wavelength difference at that point, so the wavelength must be .25m.
The frequency is double, 1372Hz.   

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