1. You and a friend are studying late at night. There are three 150 W light bulb

Question

1. You and a friend are studying late at night. There are three 150 W light bulbs and a radio with an internal resistance of 79.0 ? plugged into the living room electrical outlets. You decide to have a break and have a snack, turning on the pop-corn machine that draws 9.00 A. How much electrical power are you using? Data: Assume the electric company provide you with 110 V potential difference.

2. All the electrical outlets are part of the same 110-V circuit which has a 10-A circuit breaker. How much current in amperes (A) is required to feed all the devices described above? This tells you if you should or should not turn on the pop-corn machine.

3. You are so tired after studying that you leave all of these household devices turned on for 13.0 hours. Calculate the cost (in dollars) of the electric bill, if the commercial rate is $.09/kWh? (Do not enter units)

Explanation / Answer

1) P(total) = (160*3) + P(radio) + P(pop-corn machine)

P(radio) = V^2/r
= (110^2)/79
= 153.16

P(popcorne Machine= V*I

= 110*9

= 990

P(total) = 480 + 153.16 + 990
= 1623.16 W

2)P(bulb) = V(bulb) * I(bulb)

110 = (110) * I(bulb)
I(bulb) = 1 A
Hence three bulbs will use 3.00 A.

P(radio) = V(radio) * I(radio)
153.16 = (110) * (I_radio)
I_radio = 153.16 / 110= 1.40 A??

I_microwave = 9.00 A??(given)


Now to find the total current,
I_total = 3*(I_bulb) + I_radio + I_microwave = 3.00 + 1.40 + 9.00 = 13.40A?

3)Total Cost = (Total Power) * (Cost per hour) * (Total hours)

Cost = 1623.16 * 0.09 * 13.0 = 1,899.09 $?

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