1. Two waves are generated on a string of length 3.0 m to produce a three-loop s

Question

1. Two waves are generated on a string of length 3.0 m to produce a three-loop standing wave with an amplitude of 4.6 cm. The wave speed is 123 m/s. Let the equation for one of the waves be of the form y(x, t) = ym sin (kx + ?t). In the equation for the other wave, what are (a)ym, (b)k and (c)?.

2. What are (a) the lowest frequency, (b) the second lowest frequency, and (c) the third lowest frequency for standing waves on a wire that is 11.8 m long, has a mass of 182 g, and is stretched under a tension of 156 N?

Explanation / Answer

standing wave is formed when other wave is ym sin (kx - ?t).

so ym = 4.6/2 = 2.3 cm

k = 2 pi/lambda = 2pi/(2*3/3) = pi

c =w/k

w = 123*pi

2. f = (n/2L)*?(T/?)

f = (n/2*11.8) *sqrt(156*11.8/0.182)

f = 593.36*n

so put n=1 for lowest , n=2 for next lowest and so on

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