%3Cp%3E%3Cimg%20src%3D%22https%3A%2F%2Floncapa2.physics.sc.edu%2Fres%2Fsc%2Fgbla
ID: 2274210 • Letter: #
Question
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3BVerdana%2C%26nbsp%3BArial%2C%26nbsp%3BHelvetica%2C%26nbsp%3Bsans-serif%3B%26nbsp%3Bfont-size%3A%26nbsp%3B13px%3B%26nbsp%3Bline-height%3A%26nbsp%3B17.263999938964844px%3B%22%3E%3Cp%3E%3Cbr%3E%3Ca%26nbsp%3Bname%3D%2217%22%26nbsp%3Bstyle%3D%22cursor%3A%26nbsp%3Bpointer%3B%26nbsp%3Bfont-family%3A%26nbsp%3BVerdana%2C%26nbsp%3BArial%2C%26nbsp%3BHelvetica%2C%26nbsp%3Bsans-serif%3B%26nbsp%3Bfont-size%3A%26nbsp%3B13px%3B%26nbsp%3Bline-height%3A%26nbsp%3B17.263999938964844px%3B%22%3E%3C%2Fa%3E%3C%2Fp%3EExplanation / Answer
a)
a = (3.62 + (0.43)(0.840 - 4.85)(9.80665) / (3.62 + 0.840 + 4.85)
a ? m/s^2
b)
Tleft ? (4.85 kg)(9.80665 - 1.003628)
Tleft ? 42.69466 N ? 42.7 N
c)
Tright ? (3.62 kg)(9.80665 + 1.003628)
Tright ? 39.13321 N ? 39.1 N
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