A long conducting circular rod is inside a long conducting square enclosure. The

Question

A long conducting circular rod is inside a long conducting square enclosure.

The rod is maintained at a potential of -5000 volts with respect to the square which is grounded (V=0). The contour lines are equipotentials with V = -4000, -3000, -2000, and -1000 volts.

PART A

Select a response for each statement below. (Use 'N', North, towards top of page (+y dir), and 'E', East, to the right (+x dir), 'NE' for in between 'N' and 'E', etc.)

1) The direction of the force on a small (+) charge at 2 is ....

2) The direction of the E-field at 9 is ....

4) The direction of the force on a small (-) charge at 1 is ....

5) The x-component of the E-field at 1 is zero.

6) The y-component of the E-field at 6 is negative.

7) The magnitude of the E-field at 6 is greater than that at 8 Submit Answer Tries 0/15

PART B

Calculate the work which would be required to move a charge Q = 70.5 nC from '7' to '9'.

A long conducting circular rod is inside a long conducting square enclosure. The rod is maintained at a potential of -5000 volts with respect to the square which is grounded (V=0). The contour lines are equipotentials with V = -4000, -3000, -2000, and -100 volts Select a response for each statement below. (Use 'N', North, towards top of page (+y dir), and 'E', East, to the right (+x dir), 'NE' for in between 'N' and 'E', etc.) The direction of the force on a small (+) charge at 2 is .... The direction of the E-field at 9 is .... The magnitude of the E-field at 4 is very small (~ zero). The direction of the force on a small (-) charge at 1 is .... The x-component of the E-field at 1 is zero. The y-component of the E-field at 6 is negative. The magnitude of the E-field at 6 is greater than that at 8 Submit Answer Tries 0/15

Explanation / Answer

part a

1. W , towards the rod

2. NE

3. well it's small because the contour lines stretch out ... but I wouldn't call it zero

4. S

5. true

6. true, the field points towards the rod

7 false

part (b)   

(70.5 * 10^-9 C)(2000 v) = 1.41 * 10^-7 J

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