I\'m having issues with two problems regarding electric field. I got the answer

Question

I'm having issues with two problems regarding electric field.

I got the answer 4500 which is wrong. I even tried using k as 8.9x10^9 and that gave me the wrong answer as well.

I used: E=kq/r^2

2.

Instead of a proton, where would you place an electron to produce this field at the origin?
<0,-1.70e-7,0>     <- my answer

(Hint: This problem will be much easier if you draw a diagram.)

I used E=kq/y^2

Then solved for y

Thank you.

A particle with charge +5 nC (a nanocoulomb is 1 10-9 C) is located at the origin. What is the electric field due to this particle at a location m? I got the answer 4500 which is wrong. I even tried using k as 8.9x10^9 and that gave me the wrong answer as well.

Explanation / Answer

as charge is +ve,electric field will be away from the charge.

magnitude=9*10^9*5*10^(-9)/(0.1^2)=4500 N/C

and direction will be along +ve x-axis.

so as field is a vector,you can try the answer

<4500,0,0>

2)

as field is along +ve y-axis,charge should be placed somewhere on the -ve y-axis.

let the position be <0,-d,0>

then 9*10^9*1.6*10^(-19)/(d^2)=5*10^4

d=1.697*10^(-7) m

so position is <0,-1.697*10^(-7),0>

3) instead of a proton,if you are using electron,

it is of -ve charge.

so field will be towards it.

so to get +ve field at origin which has a direction towards +ve y-axis,you need to place the electron at +ve y-axis.

so point will be <0,1.697*10^(-7),0>

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