In the figure, a ball is thrown leftward from the left edge of the roof, at heig

Question

In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 1.17 s. later, at distance d = 21.5 m from the building and at angle ? = 52 In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 1.17 s. later, at distance d = 21.5 m from the building and at angle ? = 52 In the figure, a ball is thrown leftward from the left edge of the roof, at height h above the ground. The ball hits the ground 1.17 s. later, at distance d = 21.5 m from the building and at angle ? = 52 Degree with the horizontal. What is the velocity at which the ball is thrown? Is that angle above or below the horizontal?

Explanation / Answer

a)Ux=d/t=21.5/1.17 m/s=18.367 m/s.

Velocity of ball when it hits ground(V)=Ux/cos52=29.848 m/s.

So, Vy=Vsin52=23.52m/s.

So initial velocity in y-direction(Uy)=Vy-gt=12.054m/s.

So initial velocity(U)=sqrt(Ux^2+Uy^2)=21.96m/s.

angle from horizontal =tan^-1(Uy/Ux)=33.27 degrees. below horizontal

h=Uyt+0.5*g*t^2=20.81m

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