Fairgoers ride a Ferris wheel with a radius of 6.00 m (Figure 4-18), the bottom

Question

Fairgoers ride a Ferris wheel with a radius of 6.00 m (Figure 4-18), the bottom of which is 1.75 m above the ground. The wheel completes one revolution every 34.0 s.

Fairgoers ride a Ferris wheel with a radius of 6.00 m (Figure 4-18), the bottom of which is 1.75 m above the ground. The wheel completes one revolution every 34.0 s. What is the average speed of a rider on this Ferris wheel? If a rider accidentally drops a stuffed animal at the top of the wheel, where does it land relative to the base of the ride? (Neglect air resistance.)

Explanation / Answer

a)angular speed w=2pi/34=0.1848 rad/s.

average speed(v)=w*R=1.109m/s.

b)height of object from ground(h)=2R+1.75=13.75m

So,h=0.5*g*t^2

So,t=1.675s.

So, d=v*t=1.858m.

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