Suppose we draw the right circular cylinder shaped Gaussian surface so that only

Question

Suppose we draw the right circular cylinder shaped Gaussian surface so that only the positive plate is contained therein. We find the electric field is (check all correct answers)

Suppose we draw the right circular cylinder shaped Gaussian surface so that only the positive plate is contained therein. We find the electric field is (check all correct answers) Inside the plates, it has magnitude , but outside it has magnitude. Only outside the plates, with magnitude .Only between the plates, with magnitude , and pointing from negative to positive, i.e. perpendicular to the plates. Only between the plates, with magnitude and pointing from positive to negative, i.e. perpendicular to the plates. Zero everywhere. Only outside the plates, with magnitude

Explanation / Answer

because outside the electric fields by the paltes cancel each other but inside they add up and point from postive to negative

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