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Question

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Refer to Interactive Solution 19.25 to review one way in which this problem can be solved. Two protons are moving directly toward one another. When they are very far apart, their initial speeds are 1.20 x 105 m/s. What is the distance of closest approach?

Number Units No unitssmm/sNJWN/CC Refer to Interactive Solution 19.25 to review one way in which this problem can be solved. Two protons are moving directly toward one another. When they are very far apart, their initial speeds are 1.20 times 105 m/s. What is the distance of closest approach?

Explanation / Answer

Kinetic energy is transformed to potential energy
2(1/2mv^2) = kQ^2/R
R = kQ^2/(mv^2) = 8.988 x 10^9 x (1.602 x 10^-19)^2/(1.673 x 10^-27 x 1.80106) = 0.077 m

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