ANSWERS MUST BE CORRECT: Points will be awarded to the individual with all parts

Question

ANSWERS MUST BE CORRECT:

Points will be awarded to the individual with all parts of the question correct. Thanks!

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Two small plastic balls hang from threads of negligible mass. Each ball has a mass of 0.170 g and a charge of magnitude q.

The balls are attracted to each other, and the threads attached to the balls make an angle of 20.0 ? with the vertical, as shown in the figure.  (Figure 1)

Part A:

Find the magnitude of the electric force acting on each ball.

F = ???   N

Part B:

Find the tension in each of the threads.

T = ???   N  

Part C:

Find the magnitude of the charge on the balls.

q =  ???   nC  

Explanation / Answer

m = 0.17*10^-3 kg

let T is the tension in the threads

Fnety = 0

T*cos(20) - m*g = 0

B) T = m*g/cos(20) = 0.17*10^-3*9.8/cos(20) = 1.773*10^-3 N <<<---Answer

Fnetx = 0

A) T*sin(20) - Fe = 0

Fe = T*sin(20) = 1.773*10^-3*sin(20) = 0.606*10^-3 N <<<<-Answer


C)
T*sin(20) = Fe


T*sin(20) = k*q^2/0.0205^2

q = sqrt(T*sin(20)*0.0205^2/k)

= sqrt(1.773*10^-3*sin(20)*0.0205^2/9*10^9)

= 5.32*`10^-9 C

= 5.32 nC <<<<<<<<<<<--Answer

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