the second part of the question is correct. i just can\'t get the first part. A
ID: 2271056 • Letter: T
Question
the second part of the question is correct. i just can't get the first part.
A particle that carries a net charge of -23.8 /vC is held in a region of constant, uniform electric field. The electric field vector is oriented 70.2degree clockwise from the vertical axis, as shown. If the magnitude of the electric field is 9.32 N/C, how much work is done by the electric field as the particle is made to move a distance of d = 0.756 m straight up? What is the potential difference between the particle's initial and final positions (Vf - Vj)?Explanation / Answer
W = F D COS 70.2 = q E D COS 55.2 = 23.8 * 10^-6 * 9.32 * 0.756 * cos 70.2
W=5.68*10^-5
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