heeelp clear answer please 21-45 A -4.00-muC charge lies 20.0 cm to the right of
ID: 2270951 • Letter: H
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21-45
A -4.00-muC charge lies 20.0 cm to the right of a 2.00-muC charge on the x-axis. What is the force on the 2.00-muC charge? Two initially uncharged identical metal spheres, 1 and 2, are connected by an insulating spring (unstretched length L0 = 1.00 m, spring constant k = 25.0 N/m), as shown in the figure. Charges +q and -q are then placed on the spheres, and the spring contracts to length L = 0.635 m. Recall that the force exerted by a spring is Fs = kAx, where Ax is the change in the springs length from its equilibrium length. Determine the charge q. If the spring is coated with meta l o make it conducting, what is the new length of the spring?Explanation / Answer
21.44 ) F= kQ1Q2 /r^2 = 9 x 10^9 x 2 x 10^-6 x -4 x 10^-6 /(0.2^2)
= -0.45 N
negative sign indicates force of attraction. i.e. force is towars -4 uC charge
21.45 ) force between spheres after cherges introduce = kQ1Q2/r^2
= 9 x 10^9 x q x (-q) /0.635^2 =- 2.232 x 10^10 q^2
negative sign indicates force of attraction.
this force is balanced by spring force = kx =25 x (L0-L1)=25(1-0.635)=9.125 N
=> 2.232 x 10^10 q^2 = 9.125 => q = 20.219 uC
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