A weather balloon contains 12.0 m 3 of hydrogen gas when the balloon is released

Question

A weather balloon contains 12.0 m3 of hydrogen gas when the balloon is released from a location at which the temperature is 22.0C and the pressure is 101 kPa. The balloon rises to a location where the temperature is -30.0C and the pressure is 20.0 kPa. If the balloon is free to expand so that the pressure of the gas inside is equal to the ambient pressure, what is the new volume of the balloon? Assume that in both cases the hydrogen gas is in thermal equilibrium with the outside air. A weather balloon contains 12.0 m3 of hydrogen gas when the balloon is released from a location at which the temperature is 22.0C and the pressure is 101 kPa. The balloon rises to a location where the temperature is -30.0C and the pressure is 20.0 kPa. If the balloon is free to expand so that the pressure of the gas inside is equal to the ambient pressure, what is the new volume of the balloon? Assume that in both cases the hydrogen gas is in thermal equilibrium with the outside air.

Explanation / Answer

As we know, PV = nRT

As n and R are constants, so we have

P1V1/T1 = P2V2/T2

(101*12)/(273+22) = (20*V)/(273-30)

Therefore,

V = 49.9179661 m3

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