Work Through this step by step please while explaining it Consider the setup of

Question

Work Through this step by step please while explaining it

Consider the setup of a gun aimed at a target (such as a monkey) as shown in the figure. The target is to be dropped from the point A at t = 0, the same |moment as the gun is fired. The bullet hits the target at a point P, which is at the same horizontal level as the gun. Let the initial speed of the bullet be vq, let the angle between the vector vo and the horizontal (x-) direction be 9, and OP = L and AP = h. The gravitational acceleration is g. Denote the time taken to hit the target byT. The acceleration of gravity is 9.8 m/s2 .

Explanation / Answer

The time taken to hit the target = Time taken by target to reach P from A

S = ut + (1/2)at^2

-H = 0 + (1/2)(-g)t^2

H = (1/2)gt^2

t = sqrt( 2H/g )

So, time taken to hit the target = sqrt( 2H/g )

Option 5.

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