As defined in Chapter 6, the work done by a force on an object is equal to the f

Question

As defined in Chapter 6, the work done by a force on an object is equal to the force times the displacement times the cosine of the angle between the force and displacement vectors (W=F

As defined in Chapter 6, the work done by a force on an object is equal to the force times the displacement times the cosine of the angle between the force and displacement vectors (W=F middot dcos(?)). Suppose you are supporting a 1.41-kg block. What is the gravitational force (magnitude and direction) acting on the block? 13.8 N If you lower the block a distance of 0.220 m, what is the work done by the gravitational force as you lower the block? 3.04 J What is the value of the angle ? (in degrees - do not enter units)?

Explanation / Answer

1). force= m*g

= 1.41*9.8

=13.818 N

2). work done = F.d

=13.818*.22

3.04 J

3). angle is zero degree

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