A particle with mass 2.40 g and charge +10.0 A particle with mass 2.40 g and cha

Question

A particle with mass 2.40 g and charge +10.0

A particle with mass 2.40 g and charge +10.0 mu C enters through a small hole in a metal plate with a speed of 7.50 m/s at an angle of 55 degree. The uniform field in the region above the plate has magnitude 6.00 103 N/C and is directed downward. The region above the metal plate is essentially a vacuum, so there is no air resistance. Can you neglect the force of gravity when solving for the horizontal distance traveled by the particle? Why or why not? How far will the particle travel, ?x, before it hits the metal plate? m

Explanation / Answer

ay = q E/m = 10.0E-6*6.0E3/2.4E-3= 25 m/s^2

a) no since ay is not big compared to g

b) y direction
y = y0 + v0y t + 1/2 a t^2

0 = 0 + 7.5*sin(55)*t - 0.5*(25 + 9.81)*t^2

t=0.353 s

x = 7.5*cos(55)*0.353= 1.52 m

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