GIVEN 2 ANSWERS BELOW ARE WRONG! I NEED SOMEONE TO SOLVE THIS. :) Thank you when

Question

GIVEN 2 ANSWERS BELOW ARE WRONG! I NEED SOMEONE TO SOLVE THIS. :) Thank you

when k =1.50. (Take = 23.0°.)

= ?

2Fcos23+ Fa = 2Fa

2Fcos20 = Fa

F/Fa = 1/(2cos23) 0.543

1.50 * Fa = Fa + 2 * F * cos23 = Fa + 1.84F

1.50 * Fa = 1.84F

F/Fa = 0.815

F FA A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply a force F rightarrow A, as part a of the drawing shows. By itself, however, force F rightarrow A is insufficient. Therefore, two additional forces F rightarrow B and F rightarrow C are applied, as in part b of the drawing. Each of these additional forces has the same magnitude F. The magnitude of the resultant force acting on the elephant in part b of the drawing is k times larger than that in part a. Find the ratio when k =1.50. (Take I ^¸ = 23.0 A ^ degree .) = ? 2Fcos23+ Fa = 2Fa 2Fcos20 = Fa F/Fa = 1/(2cos23) a^ 0.543 1.50 * Fa = Fa + 2 * F * cos23 = Fa + 1.84F 1.50 * Fa = 1.84F F/Fa = 0.815

Explanation / Answer

2Fcos23+ Fa = 2Fa

2Fcos20 = Fa

F/Fa = 1/(2cos23) 0.543

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