The component values applicable to the circuit in questions 1-14 are: R 1 = 2.00

Question

The component values applicable to the circuit in questions 1-14 are:

R1 = 2.00
R2 = 3.90
R3 = 8.20
L1 = 16.10 H

1. Find the reading of voltmeter V1 immediately after switch S is closed.

2. Find the reading of voltmeter V2 immediately after switch S is closed.

3. Find the reading of voltmeter V3 immediately after switch S is closed.

4. Find the reading of voltmeter V4 immediately after switch S is closed.

5. Find the reading of ammeter A1 immediately after switch S is closed.

6. Find the reading of ammeter A2 immediately after switch S is closed.

7. Find the reading of ammeter A3 immediately after switch S is closed.

In questions 8-14 you will be analysing the circuit after switch S has been closed for a very long time (i.e. t ).

8. Find the reading of voltmeter V1 after switch S has been closed for a very long time.

9. Find the reading of voltmeter V2 after switch S has been closed for a very long time.

10. Find the reading of voltmeter V3 after switch S has been closed for a very long time.

11. Find the reading of voltmeter V4 after switch S has been closed for a very long time.

12. Find the reading of ammeter A1 after switch S has been closed for a very long time.

13. Find the reading of ammeter A2 after switch S has been closed for a very long time.

14. Find the reading of ammeter A3 after switch S has been closed for a very long time.

PLEASE WRITE LEGIBLY AND DESCRIBE EVERYTHING YOU ARE DOING WITH FORMULAS NOT JUST NUMBER. THANKS

Consider the circuit shown below, consisting of 3 resistors, one inductor (L,), an external emf of 5.00 V, and a set of ideal voltmeters and ammeters. You should use this circuit to answer questions 1-14 R3 5.00 V R2 V. In each case, enter currents in Amps and voltages in Volts, but DO NOT include the units in your answer (decimal numbers only). In questions 1-7 you will be analysing the circuit immediately after switch S is closed (i.e.t 0).

Explanation / Answer

at t = 0, when the switch is immidiately closed

the capacitors acts like closed switch and inductor acts like open switch

R1 = 2 ohm

R2 = 3.9 ohm

R3 = 8.2 ohm

L1 = 16.1 H

1. hence, there is no current in the middle branch

V1 = i*R1

also

5 = i(R1 + R3)

hence

i = 0.490196 A

so, V1 = 0.980392156 V

2. V2 = V4 ( as ther is no curren tin the middl ebranch)

V4= 5 - V1 = 4.01960784 V

V2 = 4.019607 V

3. V3 = 0 V ( curent is 0)

4. V4 = 4.019607 V

5. A1 = i = 0.490196 A

6. A2 = 0 A

7. A3 = A1 = 0.490196 A

at t = inf, the inductor acts as closed switch

8. V1 = iR1

5 = i(R1 + R2*R3/(R2+R3)) = 4.6429752i

hence

i = 1.076895 A

V1 = 2.153791384 V

9. V2 = 0 V ( as inductor is acting like closed switch)

10. V3 = 5 = V1 = 2.8462 V

11. V4 = V3 = 2.8462 V

12. A1 = i = 1.076895 A

13. A2 = V3/R2= 0.72979487 A

14. A3 = A1 - A2 = 0.3471 A

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