Hello, I\'ve posted this question for matlab code but matlab doesn\'t accept neg

Question

Hello, I've posted this question for matlab code but matlab doesn't accept negative values or zeros,here is the code like here (m(-1) = 0;)

m(-1) = 0;

m(2) =0;

for k = 0:3

if (k==0)

e(k) = 1;

m(k) = e(k)+m(k-1)+m(k-2);

else

e(k) = 0;

m(k) = e(k)+m(k-1)+m(k-2);

end

StudefHl ID Recal, an a linear and time invariant DT systems can be modeled by a difference equation with constant coefficients of the form y(k)-yo ba(k-i)-y.lajy(k-j) for k=0, 1,2,.." Part I (in-class 1. Identify the orders (m ad n) of the following difference equation: y(k #3)-6y( k ) + y(k-1) = x(k) orders 2. Write a different equation with order of m=2 and n=2 3. A digital filter is described by the following difference equation m(k)-m( k-1) + m(k-2)-e(k ): k 0, 1,2,3, a. solve for the first four values of m(k) using the sequential technique if the with m(-1 ) = m(-2) = 0 mco) -o-o = 1 Part II (take home assignment) m2)-m(-1), Write a MTALB program that calculate m (k) in part (3) Please submit the take-home part no later in class on Wed Feb 7 2018

Explanation / Answer

The code is a general purpose code which can be extended to any order with change in equation only.

Code:

clc
clear all
close all
%since matlab cannot take less than & equal to 0 indices. We consider
%initial condition start from order of the system.
ord=input('Enter Order of the system: ');
for j=1:ord;
m(j)=0;
end
e(1)=1;
for i=ord+1:ord+4;
if(i==ord+1)
e(i-ord)=1;
else
e(i-ord+1)=0;
end
m(i)=e(i-ord)+m(i-1)-m(i-2);
end
fprintf('The first four values of m(k) are: ' )
disp(m(ord+1:end))

Output:

Enter Order of the system: 2
The first four values of m(k) are:
1 1 0 -1

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