1. You\'re working with an accelerometer that has an input of 0-4 g (\"g\"-gravi
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1. You're working with an accelerometer that has an input of 0-4 g ("g"-gravitational unit, or 1 "g" = 9.81 m/s) and an output of 0-10 V. For the experimental conditions of the accelerometer. you expect the acceleration to range between 1 - 2.5 g. You have the choice of three ADC units to use; model the response of each ADC similar to the explanation in the videos and textbook. Unit 1: Input range: 0 to +5 V; 8 bits Unit 2: Input range: 0 to +10 V; 10 bits » Unit 3: Input range: -10 to +10 V; 12 bitsExplanation / Answer
e) 0-4g corresponds to 0-10v.
It is a linaer scale. Thus 2.5g wwill correspond to 10V*2.5/4 = 6.25V
Unit 1: As input range is 0-5V, 6.25V can't be read and it will read 5V with ADC count of 11111111 with significant error.
Unit 2: As input range is 0-10V, 6.25V can be read and it will read 6.25V with ADC count as binary count of 6.25*210/10 = binary count of 640 calculated by successive approximation method as 101000i1111 with less error.
Unit 3: As input range is -10-10V, 6.25V can be read and it will read 6.25V with ADC count as binary count of 6.25*211/10 = binary count of 1280 calculated by successive approximation method as 010100011110 with further less error. NOTE: Here the first digit is used for sign and 0 indicates positive value
f) the difference in value is explained as differnce in significant digits.
g) the accleartion error is 2 times less for unit 3 as compared to unit 2 due to extra bit.
h) If accuracy is a factor chose unit 3 which is 2 times more accurate or else go for unit 2 if cost ia factor.
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