6. 6. 6. A 3.80-kg cyli+B844ndrical rod of length 2.00 m is suspended from a hor

Question

6. 6. 6. A 3.80-kg cyli+B844ndrical rod of length 2.00 m is suspended from a horizontal bar so it is free to swing about that end. A solid sphere of mass 0.25 kg is thrown horizontally with a speed v1 = 16.0 m/s to hit the rod at the point A one-fifth of the way up from the bottom of the rod. The sphere bounces back horizontally with a speed v2 = 9.50 m/s, while the rod swings to the right through an angle ? before swinging back toward its original position. What is the angular velocity of the rod immediately after the collision? rad/s

Explanation / Answer

usingangular momentum conservation ,

initial = final

mvi x 4d/5 + 0 = - mvf 4d/5 + 3.80 x d^2 /3 x w

3.80 x 2^2 x w / 3 = 0.25 x 16 x 4 x 2 /5 + 0.25 x 9.5 x 4 x 2 /5

w = 2.01 rad/s

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