In a velocity selector, the uniform magnetic field of 1.8 T is produced by a lar

Question

In a velocity selector, the uniform magnetic field of 1.8 T is produced by a large magnet. Two parallel plates with a separation of 1.6 cm produce the perpendicular electric field.

In a velocity selector, the uniform magnetic field of 1.8 T is produced by a large magnet. Two parallel plates with a separation of 1.6 cm produce the perpendicular electric field. What voltage should be applied across the plates so that a singly charged ion traveling at 6.90 Times 104 m/s will pass through undeflected? V What voltage should be applied across the plates so that a doubly charged ion traveling at the same speed will pass through undeflected? V

Explanation / Answer

electric force(Fe) =magnetic force(FB)

q*E=B*q*v

where

q is charge

E is electric field

B is magnetic field=1.8 tesla

v is speed

but voltage difference delV=E*d

where d =1.6 cm=1.6*10^-2 m

q*(delV/d)=B*q*v

so,

q*delV/d=B*q*v

====>

delV=B*v*d

a)

v=6.9*10^4 m/sec

delV=B*v*d

=1.8*6.9*10^4*1.6*10^-2

=19.872 *10^2 volts

=1987.2 volts

b)

some voltage

deltaV = 1987.2 volts

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