with units Use the following values if needed: 1 foot = 0.30 meter 1 hp = 746 wa

Question

with units

Use the following values if needed: 1 foot = 0.30 meter 1 hp = 746 watt (W) 1 cal = 42 joule g = 9.80 m/s2 G = 6.67x10-11 N m2/kg2 Some moments of inertia (about centers): disk (1/2)MR2 sphere (2/5)MR2 Standard atmosphere = 1.013x105 N/m2 Absolute zero = -273 degree C Density of water = 1000 kg/m3 Density of air = 1.29 kg/m3 (standard temperature, pressure) A lakeside pier was extended by loosely tying a rectangular 'float' to its end. If the 'float' is 2.5 m long, weighs 882 N, and like an iceberg floats with only one-tenth of its 10-cm height above water, how wide is it? A ranch water storage tank is an elevated open tub with an area of 6 m2. A single pipe of area 4 cm2 is drawing water from it; the water is flowing through the pipe at 8 m/s. What is the absolute pressure in the pipe at a point 5 m below the tub's water level?

Explanation / Answer

weight=volume of water dispersed

then if width is d,

then 2.5*d*0.1*(1/10)*1000*9.8=882

so d=3.6 m

2.area=6 m^2

area of pipe=4*10^(-4) m^2

using bernoulii's principle:

1.013*10^5+10^3*9.8*5=P+(8^2/(2*9.8))

P=1.50296*10^5 N/m^2

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.