In the figure above, a long straight wire carries a current of I a = 5.00 A. A s

Question

In the figure above, a long straight wire carries a current of Ia= 5.00 A. A square loop with a side of length 0.250m is placed a distance 0.100 m away from the wire. The square loop carries a current Ib=2.60 A.

Find the magnitude of the net force on the square loop.
        

In the figure above, a long straight wire carries a current of Ia= 5.00 A. A square loop with a side of length 0.250m is placed a distance 0.100 m away from the wire. The square loop carries a current Ib=2.60 A. Find the magnitude of the net force on the square loop.

Explanation / Answer

force between two parallel wires is given by F = u0i1i2l/(2pir)

here one set of parallel wires are separated by 0.1m

and another set of parallel wires are separated by (0.1+0.25) = 0.35 m

force due to the other two set of opposites cancels to zero

FNet = F1-F2

F1 = 4pi*10^-7 *5*2.6 *0.25/(2pi 0.1)

F1 = 6.5 *10^-6 N

F2 = 4pi*10^-7 *5*2.6 *0.25/(2pi 0.35)

F2=1.8*10^-6 N

F1 is opposite to F2

so Fnet = F1-F2 =4.7 *10^-6 N

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