Problem 24.64 An object is placed 22.0 c m from a screen. Part A At what two poi

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Problem 24.64 An object is placed 22.0cm from a screen. Part A At what two points between object and screen may a converging lens with a 4.00cmfocal length be placed to obtain an image on the screen? Enter your answer as two numbers, separated with a comma. Count the distances from the object.   s1, s2 =   cm   SubmitMy AnswersGive Up Part B What is the magnification of the image for each position of the lens? Enter your answer as two numbers, separated with a comma.   m1, m2 = SubmitMy AnswersGive Up
Please show your work. Thank you! OPL Problem 24.64 An object is placed 22.0cm from a screen. Problem 24.64 An object is placed 22.0cm from a screen. An object is placed 22.0cm from a screen. An object is placed 22.0cm from a screen. Part A At what two points between object and screen may a converging lens with a 4.00cmfocal length be placed to obtain an image on the screen? Enter your answer as two numbers, separated with a comma. Count the distances from the object.   s1, s2 =   cm   SubmitMy AnswersGive Up Part B What is the magnification of the image for each position of the lens? Enter your answer as two numbers, separated with a comma.   m1, m2 = SubmitMy AnswersGive Up
Please show your work. Thank you! OPL Part A At what two points between object and screen may a converging lens with a 4.00cmfocal length be placed to obtain an image on the screen? Enter your answer as two numbers, separated with a comma. Count the distances from the object.   s1, s2 =   cm   SubmitMy AnswersGive Up Part B What is the magnification of the image for each position of the lens? Enter your answer as two numbers, separated with a comma.   m1, m2 = SubmitMy AnswersGive Up
Please show your work. Thank you! OPL Part A At what two points between object and screen may a converging lens with a 4.00cmfocal length be placed to obtain an image on the screen? Enter your answer as two numbers, separated with a comma. Count the distances from the object.   s1, s2 =   cm   SubmitMy AnswersGive Up Part B What is the magnification of the image for each position of the lens? Enter your answer as two numbers, separated with a comma.   m1, m2 = SubmitMy AnswersGive Up
Please show your work. Thank you! OPL Part A At what two points between object and screen may a converging lens with a 4.00cmfocal length be placed to obtain an image on the screen? Enter your answer as two numbers, separated with a comma. Count the distances from the object.   s1, s2 =   cm   SubmitMy AnswersGive Up Part B What is the magnification of the image for each position of the lens? Enter your answer as two numbers, separated with a comma.   m1, m2 = SubmitMy AnswersGive Up
Please show your work. Thank you! OPL Part A At what two points between object and screen may a converging lens with a 4.00cmfocal length be placed to obtain an image on the screen? Enter your answer as two numbers, separated with a comma. Count the distances from the object.   s1, s2 =   cm   SubmitMy AnswersGive Up Part A At what two points between object and screen may a converging lens with a 4.00cmfocal length be placed to obtain an image on the screen? Enter your answer as two numbers, separated with a comma. Count the distances from the object.   s1, s2 =   cm   SubmitMy AnswersGive Up   s1, s2 =   cm     s1, s2 =   cm   SubmitMy AnswersGive Up Part B What is the magnification of the image for each position of the lens? Enter your answer as two numbers, separated with a comma.   m1, m2 = SubmitMy AnswersGive Up
Please show your work. Thank you! OPL Part B What is the magnification of the image for each position of the lens? Enter your answer as two numbers, separated with a comma.   m1, m2 = SubmitMy AnswersGive Up
Please show your work. Thank you! OPL   m1, m2 =   m1, m2 = SubmitMy AnswersGive Up
Please show your work. Thank you! OPL   s1, s2 =   cm  

Explanation / Answer

S = x

S' = 22-x

1/S + 1/S' = 1/F

1/x + 1/(22-x) = 1/4

(22-x+x)4 = (22-x)*x

88 = 22x-x^2

x^2 - 22x+88 = 0

x =16.74 cm or 5.25 cm

B)
for x = 16.74

S1 = 16.74 and S1' = 22-16.74 = 5.26 cm

m1 = S1'/S1 = 0.314

S2 = 5.26 and S2' = 16.74 cm

m2 = S2'/s2 = 3.182

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