Question
HELP PLEASE ! thanks in advance
The velocity of an object in simple harmonic motion is given by v(t)=-(3.19m/s) sin(21.0t + 2.00 Phi ), where t is in seconds. What is the first time after t=0.00 s at which the velocity is -0.367m/s? 5.49*10-3 s Previous Tries What is the Object's position at that time? Tries 2/10 Previous Tries What is the frequency of the oscillation shown if t1=50.2s and A=10.0cm? Tries 2/10 What is the phase constant? Use the cosine function y=A cos(omega t phi) to describe the simple harmonic motion. Tries 0/10 what is the phase at t1? Tries 0/10 A mass, m1 = 8.73kg, is in equilibrium while connected to a light spring of constant k = 103N/m that is fastened to a wall, as shown in the figure (part a) below. A second mass, m2 = 7.16kg, is slowly pushed up against mass m1r compressing the spring by the amount A = 0.182m (see figure, part b). The system is then released, and both masses start moving to the right on the frictionless surface. When m1 reaches the equilibrium point, m2 loses contact with m1 (see figure, part c) and moves to the right with speed v. Determine the value of v. 4.63X10-1 m/s Previous Tries How far apart are the masses when the spring is fully stretched for the first time (D in part d of the figure)? First determine the period of oscillation and the amplitude of the m1-spring system after m2 loses contact with m1
Explanation / Answer
Time period = t1/2 = 50.2/2 = 25.1 s
frequency = 1/T = 1/25.1 = 0.0398 Hz
