..................... You pull downward with a force of 25 N on a rope that pass

Question

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You pull downward with a force of 25 N on a rope that passes over a disk-shaped pulley of mass 1.2 kg and radius 0.075 m. The other end of the rope is attached to a 0.73-kg mass. Is the tension in the rope the same on both sides of the pulley? No, the tension on the pulling side is smaller. Yes, the tension is the same on both sides. No, the tension on the pulling side is greater. Find the tension in the rope on both sides of the pulley.

Explanation / Answer

Let tension on pulling side be T1 and that on other side be T2. T1 = 25 N for the pulley; net torque = moment of inertia*alpha => (T1 - T2)*R = [m*R^2/2]*(a/R) => 25 - T2 = (1.2/2)*a => T2 = 25 - 0.6*a for the mass; T2 - Mg = M*a => T2 - 0.73*9.8 = 0.73*a => T2 = 0.73*a + 7.154 => 25 - 0.6*a = 0.73*a + 7.154 => a = 13.42 m/s^2 T2 = 25 - 0.6*13.42 = 16.948 N a). yes, the tension on pulling side is greater b). tension on pulling side = 25 N tension on other side = 16.948 N

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