As shown in the figure below, a box of mass As shown in the figure below, a box
ID: 2263137 • Letter: A
Question
As shown in the figure below, a box of mass
As shown in the figure below, a box of mass m = 53.0 kg (initially at rest) is pushed a distance d = 72.0 m across a rough warehouse floor by an applied force of FA = 236 N directed at an angle of 30.0 degree below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) work done by the applied force work done by the force of gravity work done by the normal force work done by the force of friction Calculate the net work on the box by finding the sum of all the works done by each individual force. Now find the net work by first finding the net force on the box, then finding the work done by this net force.Explanation / Answer
N = m*g + Fsin30
a) W = Fx*d = F*cos30 *d = (F*cos30 - mue*(mg+Fsin30))*d
W = ((236*cos30))*72 = 14.715503661*10^+3 J
b) Wg = 0
c) Wn = 0
d) Wf = mue*N*d = mue*(mg+Fsin30)*d = -4.58928*10^+3 J
e) Wnet = 14.715503661*10^+3 - 4.58928*10^+3 = 10.126223661*10^+3 J
f) Wnet = Fnet*d = (F*cos30 - mue*(mg+Fsin30))*d = 10.126223661*10^+3
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