3. An experimental bicycle wheel is placed on a test stand so that it is free to

Question

3. An experimental bicycle wheel is placed on a test stand so that it is free to turn on its axle. If a constant net torque

of 5.0 N m is applied to the tire to 2.00 s the angular speed of the tire increases from rest to 100 rpm. The external

torque is then removed and the wheel comes to rest due to friction in its bearings in a time 180 s.

(i) What is the moment of inertia of the tire about its axis?

(ii) What is the torque supplied by friction?

(iii) Through how many revolutions will the tire turn in the 180 s interval?

Explanation / Answer

i)Torque = moment of inertia * angular accelaration
5 = I*(100-0)/2
I = 0.1 kg.m^2

ii)friction torque= I * angular acceleration
= 0.1*(100-0)/180
= 0.056 Nm

iii)no of revolutions = (1/2)(100/180)(180)^2
= 9000 rev

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