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Three long, parallel conductors each carry a current of I = 1.60 A. The figure b

ID: 2262400 • Letter: T

Question

Three long, parallel conductors each carry a current of I = 1.60 A. The figure below is an end view of the conductors, with each current coming out of the page. Taking a = 0.70 cm, determine the magnitude and direction of the magnetic field at the following points.

(a) point A     

magnitude 1      Three long, parallel conductors each carry a current of I = 1.60 degree A. The figure below is an end view of the conductors, with each current coming out of the page. Taking a = 0.70 cm, determine the magnitude and direction of the magnetic field at the following points.

Explanation / Answer

a)

Ba =B1cos45 +B2cos45+B3

Ba =(uoI/2pia)[sqrt(2)*cos45 +(1/3)]

Ba =(4pi*10^-7*1.6/2pi*0.7*10^-2)*1.33

Ba =60.8 uT

Direction -towards bottom of the page

b)

Bb =B3 =uoI/2pi(2a) =uoI/4pia

Bb =(4pi*10^-7)*1.6/(4pi*0.7*10^-2)

Bb =22.86 uT

Direction towards bottom of the page

c)

Bc =0


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