Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

This print-out should haw 20 questions. Multiple-choice questions may continue o

ID: 2261272 • Letter: T

Question

This print-out should haw 20 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. A force acting on an object does no work if the force acts perpendicular to the direction of the object's motion. the force is greater than the force of friction. a machine is used to move the object. the object accelerates. The amount of work done by two boys who apply 340 N of force in an unsuccessful attempt to move a stalled car is 340 N . m. 340 N. 0. 680 N . m. 680 N. A 17.3 kg block is dragged over a rough, horizontal surface by a constant force of 144 N acting at an angle of angle 33.5 degree above the horizontal. The block is displaced 64 m and the coefficient of kinetic friction is 0.218. Find the magnitude of the work done by the force of friction. Answer in units of J What is the sign of the work done by the frictional force? negative zero positive Find the work done by the normal force. Answer in units of J What is the net work done on the block? Answer in units of J A Newton-meter is a measure of work also known as the None of these Watt. Coulomb. Joule. If you exert a force of 24 N to lift a box a distance of 0.86 m, how much work do you do? Answer in units of J

Explanation / Answer

001) option 1 (if force acts perpendicular to the direction of motion)

002) 0 N (option3)

003)W(net)=W(by Force)+W(by friction)=[144cos(33.5)*64] + [-0.218(17.3*9.8-144sin(33.5))*64]=6428.562J

So W(by force)=7685.092J

W(by friction)=-1256.53J

Sign(work by friction) is negative

008) Joule (option4)

009)W=24*0.86=20.64J

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote