The projection lens in a certain slide projector is a single thin lens. A slide

Question

The projection lens in a certain slide projector is a single thin lens. A slide 23.8 mm high is to be projected so that its image fills a screen 1.81 m high. The slide-to-screen distance is 2.99 m. Determine the focal length of the projection lens. How far from the slide should the lens of the projector be placed to form the image on the screen? mm

Explanation / Answer

u + v = 2.99 m magnification m = v/u = 1.81/0.0238 = 76.05 so v = 76.05 * u u + 76.05*u = 2.99 m => u = 0.0388 m so, v = 2.99- 0.0388 = 2.9512 m (a) focal length f = u*v/(u+v) = 0.0388* 2.9512/2.99 = 0.038296 m = 38.296 mm (b) from above, distance from slide to lens is u = 0.0388 m = 38.8 mm [because of the high magnification from one lens the distances are very critical]

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