If the sun (M = 1.99 x 10^30 kg, R = 6.96x10^8m, Tspin = 25.2 days) collapses in

Question

If the sun (M = 1.99 x 10^30 kg, R = 6.96x10^8m, Tspin = 25.2 days)  collapses into a neutron start of the radius 5.km, how fast would it spin?

days?__________

Hours _______

Min __________

sec __________

msec _________

How much is the frequency of the spin ?    ____________hz    _________________kHz

I originally got 4.7 x 10^-6 days, but I have no idea if that's right.

Please answer and explain how to do this as simply as possible.  I saw a similar problem answered, but I didn't understand much of it.

Explanation / Answer

according to the conservation angular momentum

I (initial) = I ( final)

wf =((r2/r1)^2 )* wi

wi = (2*.314)/T= (3.14*2)/ 25.2

wi = 0.24

wf = ((6.96x10^8 / 5* 10 ^3) ^2) * .24

wf = 4.65 * (10^-6) days = 1.116 *(10^-4) hours

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