Zach, whose mass is 64kg , is in an elevator descending at 10m/s . The elevator

Question

Zach, whose mass is 64kg , is in an elevator descending at 10m/s . The elevator takes 5.0s to brake to a stop at the first floor.

Part 1

What is Zach's apparent weight before the elevator starts braking?

Part 2

What is Zach's apparent weight while the elevator is braking?

Zach, whose mass is 64kg , is in an elevator descending at 10m/s . The elevator takes 5.0s to brake to a stop at the first floor. What is Zach's apparent weight before the elevator starts braking? What is Zach's apparent weight while the elevator is braking?

Explanation / Answer

(1) Since the elevator is descending at constant rate, the apparent weight is same as regular weight = m*g = 64*9.8 = 627.2N

(2) To come to rest in 5s, the elevator has to decelerate at 2m/s^2.

Apparent weight = m*(g-a) = 64*(9.8-2) = 499.2N

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