some Qs for some points Procedure Hold the magnet so that the south end is about
ID: 2259893 • Letter: S
Question
some Qs for some points
Procedure Hold the magnet so that the south end is about 2 cm above the coil. Click 'Start' in DataStudio. Let the magnet drop through the coil. Data recording will begin when the magnet falls through the coil and the voltage from the coil reaches 0.05 V. Data recording will end automatically after 0.4 seconds. Examine the graph of the voltage versus time. Rescale the graph display to fit the data if necessary. In the graph display, use the cursor to select a rectangle around the first peak of the voltage plot. Set up the graph to show the area in the selected area of the curve of voltage versus time. In DataStudio, click the statistics menu button ( ) and select 'Area'. The value for 'Area' appears in the legend in the graph. DataStudio sample graphs Record the value of 'Area' for the left-hand peak. Repeat the process to find the area for the second peak. Record the value of 'Area' for the right-hand peak. Do the same process at least three times and take the average for the area in each peak. area An emf is induced by rotating a 1247 turn, 20.0 cm diameter coil in the earth's 4.33 times 10-5 T magnetic filed. What average emf is induced, given the plane of the coil is originally perpendicular to the earth's field and is rotated to be parallel to the field in 10.0 ms? A solenoid with 1200 turns per meter has a diameter of 6.00 cm. A current I = 2.49 A flows in the counterclockwise direction (when viewed from location P) in the solenoid. A rectangle loop of length L= 16.0 cm, width w = 12.5 cm, and 2 turns is centered on the axis of the solenoid. Find the magnitude of the magnetic flux through the loop. When the current is increased to 5.60 A, the magnitude of the induced emf in the rectangular loop is 116 mV. How long did it take for the current to get to this value? What is the direction of the induced current in the rectangle loop as viewed from the location P? counterclockwise clockwise no current A 183-V battery, an inductor, and a resistor are connected in series as shown in the diagram below. A two-way switch makes it possible to include or exclude the battery. The switch that had been in position 2. (Enter your answer to at least two places.) What is the voltage across the resistor at the end of five time constants? At this time, what is the voltage across the inductor? For this assignment, you submit answer by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer. Your last submission is used for used for your score. The 5.09 A current through a 1.50 H inductor is dissipated by a 2.14 Ohm resistor in a circuit like that in the figure below, with the switch in position 2. What is the initial energy in the inductor? How long will it take the current to decline to 5.00% of its initial value? Calculate the average power dissipated, and compare it with the initial power dissipated by the resistor.Explanation / Answer
first question:
emf = d(phi)/dt = N A B w = 1247 * (3.1416*0.20*0.20) * 4.33e-5 * ((3.1416/2)/10e-3) = 1.07 V
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