A simple Atwood machine consists of two masses m 1 and m 2 that are connected by

Question

A simple Atwood machine consists of two masses m1 and m2 that are connected by a string wound over a pulley, as seen in the figure below. Assume m2 is larger thanm1. Motion in the upward direction is positive. On a piece of paper, draw two free body diagrams; one for each of the masses, showing all forces acting on each mass. Then answer the following questions.

Force Direction m1a ---Select---12345678NA m2a ---Select---12345678NA m1g ---Select---12345678NA
m2g ---Select---12345678NA (m1 + m2)a ---Select---12345678NA (m1 + m2)g ---Select---12345678NA f ---Select---12345678NA T ---Select---12345678NA FN ---Select---12345678NA A simple Atwood machine consists of two masses m1 and m2 that are connected by a string wound over a pulley, as seen in the figure below. Assume m2 is larger thanm1. Motion in the upward direction is positive. On a piece of paper, draw two free body diagrams; one for each of the masses, showing all forces acting on each mass. Then answer the following questions. Identify the forces acting on the mass m1. (Select all that apply.) m1am2am1gm2g(m1 + m2)a(m1 + m2)gfTFN Using the direction rosette indicate the direction for each of the forces acting on m1 that you identified in part (a). If any of the forces listed below is not applicable, choose 'NA'. Identify the forces acting on the mass m2. (Select all that apply.) m1am2am1gm2g(m1 + m2)a(m1 + m2)gfTFN Using the direction rosette indicate the direction for each of the forces acting on m2 that you identified in part (c). If any of the forces listed below is not applicable, choose 'NA'. Suppose m1 = 8 kg and m2 = 12 kg. What is the tension in the string? T = Suppose m1 = 8 kg and m2 = 12 kg. What is the value of the acceleration? a = Suppose that m2 starts from rest at a height of 15 m. Use the kinematic equations to determine how long it takes for m2 to hit the ground.

Explanation / Answer

a) forces acting on m1 are T and m1g

b) m1a NA
m2a NA

m1g 1

m2g NA
(m1 + m2) NA

(m1 + m2)g NA

f NA

T 5

Fn NA

c) m2g and T

d) m1a NA
m2a N

m1g NA
m2g 1

m1 + m2 a NA

m1 + m2 g NA
f NA
T 5

FN NA


Let do k) first

for block 1 T - m1g = m1a

for block 2 m2g - T = m2a

so m2g - m1g = m1 a + m2 a

12*9.81 - 8*9.81 = 20*a

a=1.962 m/s^2

now j) T = m1a + m1 g = 8*(1.962+9.81)= 94.18 N

l) y = y0 + v0y t + 1/2 a t^2

0 = 12 - 0.5*1.962*t^2

t=3.498 s

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