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1. The slow cooling of a hypereutectoid steel from the y-austenite region will p

ID: 2257820 • Letter: 1

Question

1. The slow cooling of a hypereutectoid steel from the y-austenite region will produce a mircrostructure of?

a. Pearlite

b. Pearlite and Proeutectoid a-ferrite

c. Laminated eutectic structure

d. Pearlite and Proeutectic Cementite

e. y-austenite and Proeutectoid a-ferrite


2. If the tensile strength of slow cooled a-ferrite is 40,000 psi and slow cooled pearlite is 120,000 psi, estimate the tensile strength of of a slow cooled 0.20% carbon steel.

a. 33 ksi

b. 60 ksi

c. 73 ksi

d. 80 ksi

e.120 ksi


3. A carbon steel containing 1.1% C is cooled  slowly from y-austenite. The proeutectoid cementite network will be what percent(percent relative amound) of the resulting microstructure at room temperature.

a. 3.8%

b. 5%

c. 8%

d. 92%

e. 95%


4. The normalizing treatment of steels

a. involves furnace cooling from A3 and A(cm)

b.involves  cooling from above A3 and A3,1

c. generates bainite

d. air cools austenite from above A3 and Acm

e. forms martensite


5. The spheroidizing treatment of medium and high carbon steels (0.5 to 1.3% C) is used to

a. laminate the pearlite

b. form the ferrite into round globs

c. soften the ferrite

d. form the cementite into spheroids

e. improve strength


-----Choose best answer, brief reasoning to choice would be appriceated.

Explanation / Answer

1 e. y-austenite and Proeutectoid a-ferrite