... A ladybug sits at the outer edge of a merry-go-round, and a gentleman bug si

Question

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A ladybug sits at the outer edge of a merry-go-round, and a gentleman bug sits halfway between her and the axis of rotation. The merry-go-round makes a complete revolution once each second. The gentleman bug's angular speed is: half the ladybug's. the same as the ladybug's. twice the ladybug's. impossible to determine. What is the angular momentum of the ladybug-sized merry-go-round from Question 1 if we approximate it as a '2.0 kg solid disk with radius of 0.1 m? Recall from this question that the merry-go-round makes a complete revolution once each second.

Explanation / Answer

b) same as ladybugs

L = I w = 0.5*2*0.1^2*2*pi/1=0.0628

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