An 84 k g person stands on a uniform ladder 4.0 m long, that weighs 70 N , as sh

Question

An 84kg person stands on a uniform ladder 4.0mlong, that weighs 70N , as shown in the figure(Figure 1) . The floor is rough; hence, it exerts both a normal force, f1, and a frictional force, f2, on the ladder. The wall, on the other hand, is frictionless; it exerts only a normal force, f3.

An 84kg person stands on a uniform ladder 4.0mlong, that weighs 70N , as shown in the figure(Figure 1) . The floor is rough; hence, it exerts both a normal force, f1, and a frictional force, f2, on the ladder. The wall, on the other hand, is frictionless; it exerts only a normal force, f3.

Explanation / Answer

write the equilibrium force eq.

f1=W+mg=70+840=910N

f2=f3

we have taking torque 0 about foot of the ladder

910*0.6245-f3*3.8=0

f3=149.55N=f2

2)in this case only torque eq will change

70*0.624+840*0.936-3.8*f3=0

f3=218.4N=f2

f1=910N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.