A nonuniform horizontal bar of mass m is supported by two massless wires against

Question

A nonuniform horizontal bar of mass m is supported by two massless wires against gravity. The left wire makes an angle ?1 with the horizontal, and the right wire makes an angle ?2. The bar has length L. What is the position of the center of mass of the bar, measured as distance x from the bar's left end?

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A no uniform horizontal bar of mass m is supported by two massless wires against gravity. The left wire makes an angle ?1 with the horizontal, and the right wire makes an angle ?2. The bar has length L. What is the position of the center of mass of the bar, measured as distance x from the bar's left end?

Explanation / Answer

Let F? and F? be the forces exerted by lift and right wire on the bar. Both forces act upward in direction of the wires. So you can split the forces into x- and y-component.

F?x = -F?

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