What is the magnitude of the angular momentum of the 3.00 kg, 4.30 cm diameter r

Question

What is the magnitude of the angular momentum of the 3.00 kg, 4.30 cm diameter rotating disk in the figure?

Use a table of integrals to find an antiderivative. One over nine difference of two and three x plus one ninth times natural log of the absolute value of the difference of two and three x plus c minus one twenty-seventh times left parenthesis two and three a minus fraction four over difference of two and three x end fraction minus four times natural log of absolute value of difference of two and three a end value right parenthesis plus c fraction one over three times the differences of two and three x end fraction minus one third times natural log of the absolute value of the difference of two and three x plus c one ninth times left parenthesis two minus three x minus four over the difference of two and three x plus c one ninth times parenthesis two minus three x minus four over the difference of two and three x plus natural log of the absolute value of difference of two and three x end absolute value right parenthesis plus c

Explanation / Answer

Angular Momentum of a rotating body=Iw where I is the moment of inertia and w in the angular velocity

=>I=1/2*m*r*r=3*0.0215*0.0215=0.0006933

w=600*2*pi/60=62.8 rad/s

=> Angular momentum=I*w=62.8*0.0006933=0.04354 Kg*m^2/s

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.