The rigid wheel mass is accelerated by the applied force Fx. The wheel rolls wit

Question

The rigid wheel mass is accelerated by the applied force Fx. The wheel rolls without slipping so the velocity of contact point B is always zero. For the full law of kinetic energy (W1-2 = deltaKE1-2), applied to the wheel, "work" contributions to the term W1-2 will be done by Fx only f only Fx and f only Wt, Fx, FN and f A torque T is applied, sufficient to rotate the disk. An elastic linear spring is attached by a pin joint to the disk and is stretched in the initial position shown. In one revolution of the disk, the work done by the spring on the disk is equal to the change in rotational kinetic energy of the disk Equal to 2 pi T Dependent on the moment of inertia of the disk None of the above T/F_For two observers that are fixed in two different reference frames with relative translation, their observed velocity and acceleration vectors of each other will always be of eaula magnitudes but opposite directions. A ball is dropped on a rigid surface from height h and rebounds with a coef. of restitution of e. If the ball makes an infinite number of subsequent bounces of decreasing hight, the total distance traveled will be d = h[(1-e)/(1+e)] d = h[(1-e 2)/(1+e 2)] d = h[(1-e 3)/(1-e 3) None of the above The magnitude of the time derivative of a vector given by (3i-2j) ft and rotating at ohm = 10k rad/s is approximately 36.1 ft/s 30 ft/s 20 ft/s None of the above T/F_For a rigid body in translation in t X-Y plane (no rotational motion about Z), the resultant moment from the loads applied to the body, and computed about any axis parallel to z, must sum to zero.

Explanation / Answer

14. c

15.d

16.T

17.b

18.a

19.F

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